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水中的鱼A blog about resolving coding challenges
http://fisherlei.blogspot.com/
A blog about resolving coding challenges
http://fisherlei.blogspot.com/
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水中的鱼 | fisherlei.blogspot.com Reviews
https://fisherlei.blogspot.com
A blog about resolving coding challenges
水中的鱼: January 2013
http://www.fisherlei.blogspot.com/2013_01_01_archive.html
Thursday, January 31, 2013. Facebook] Products of all elements. Given an array of numbers, nums, return an array of numbers products, where products[i] is the product of all nums[j], j! Input : [1, 2, 3, 4, 5]. Output: [(2*3*4*5), (1*3*4*5), (1*2*4*5), (1*2*3*5), (1*2*3*4)]. 120, 60, 40, 30, 24]. You must do this in O(N) without using division. An explaination of polygenelubricants method is: The trick is to construct the arrays (in the case for 4 elements). My code would look something like this:. Int a...
水中的鱼: [LeetCode] LRU Cache, Solution
http://www.fisherlei.blogspot.com/2013/11/leetcode-lru-cache-solution.html
Wednesday, November 27, 2013. LeetCode] LRU Cache, Solution. Design and implement a data structure for Least Recently Used (LRU) cache. It should support the following operations:. Get the value (will always be positive) of the key if the key exists in the cache, otherwise return -1. Set or insert the value if the key is not already present. When the cache reached its capacity, it should invalidate the least recently used item before inserting a new item. 1 hashmap, 保存key和对象位置的映射. V) :key(k), value(v) {}.
水中的鱼: [LeetCode] Evaluate Reverse Polish Notation, Solution
http://www.fisherlei.blogspot.com/2013/12/leetcode.html
Friday, December 6, 2013. LeetCode] Evaluate Reverse Polish Notation, Solution. Evaluate the value of an arithmetic expression in Reverse Polish Notation. Each operand may be an integer or another expression. 2", "1", " ", "3", "*"] - ( 2 1) * 3) - 9 ["4", "13", "5", "/", " "] - (4 (13 / 5) - 6. 对于逆波兰式,一般都是用栈来处理,依次处理字符串,. 如果是操作符,则从栈中pop出来两个元素,计算出值以后,再push到栈里面,. Subscribe to: Post Comments (Atom). TAO: Facebook’s Distributed Data Store for the Social Graph. Swift: A Storage Architecture for Large Ob jects.
水中的鱼: [LeetCode] Copy List with Random Pointer, Solution
http://www.fisherlei.blogspot.com/2013/11/leetcode-copy-list-with-random-pointer.html
Sunday, November 17, 2013. LeetCode] Copy List with Random Pointer, Solution. A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. Subscribe to: Post Comments (Atom). TAO: Facebook’s Distributed Data Store for the Social Graph. Finding a needle in Haystack: Facebook’s photo storage. Cloud Design Patterns: Prescriptive Architecture Guidance for Cloud Applications. Software-defined Storage - IBM.
水中的鱼: [LeetCode] Linked List Cycle II, Solution
http://www.fisherlei.blogspot.com/2013/11/leetcode-linked-list-cycle-ii-solution.html
Saturday, November 23, 2013. LeetCode] Linked List Cycle II, Solution. Given a linked list, return the node where the cycle begins. If there is no cycle, return. Can you solve it without using extra space? 首先,比较直观的是,先使用Linked List Cycle I的办法,判断是否有cycle。如果有,则从头遍历节点,对于每一个节点,查询是否在环里面,是个O(n 2)的法子。但是仔细想一想,发现这是个数学题。 如下图,假设linked list有环,环长Y,环以外的长度是X。 现在有两个指针,第一个指针,每走一次走一步,第二个指针每走一次走两步,如果他们走了t次之后相遇在K点. 那么 指针一 走的路是 t = X nY K ①. 指针二 走的路是 2t = X mY K ② m,n为未知数. 2X 2nY 2K = X mY K. X K = (m-2n)Y ③. LeetCode] Copy L...
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水中的鱼
Thursday, October 23, 2014. CodingTMD’s Reading List. Following reading list is selected from the papers I had read in the past 3 years. It will help you to gain a basic knowledge of what happened in current industry and bring you a little sense about how to design a distributed system with certain principles. Feel free to post the good paper you had read in the comments for sharing.:). In Search of an Understandable Consensus Algorithm. Diego Ongaro, John Ousterhout, 2013. Mike Burrows, 2006. Yasushi Sa...
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