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zimpha's blog

XVI Open Cup named after E.V. Pankratiev. Grand Prix of Japan. 这套题目的来源是Japan Alumni Group Summer Camp 2015 Day 4, 我的代码可能即将会出现在这个 链接. 这里是题解时间, 英文翻译请参考之前的某篇博客. 由于还在比赛, 题解会在比赛结束后若干个小时放出, 我的代码也会放在github上. English Translation for ONTAK 2015. English Translation for Potyczki Algorytmiczne 2015. Potyczki Algorytmiczne 2015 has just begun. As usual, the statements are only in Polish. So, I will translate the problems into English for better understanding. 2015 ACM/ICPC Asia Regional Shenyang Online. 这个赛季的OpenCup...

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XVI Open Cup named after E.V. Pankratiev. Grand Prix of Japan. 这套题目的来源是Japan Alumni Group Summer Camp 2015 Day 4, 我的代码可能即将会出现在这个 链接. 这里是题解时间, 英文翻译请参考之前的某篇博客. 由于还在比赛, 题解会在比赛结束后若干个小时放出, 我的代码也会放在github上. English Translation for ONTAK 2015. English Translation for Potyczki Algorytmiczne 2015. Potyczki Algorytmiczne 2015 has just begun. As usual, the statements are only in Polish. So, I will translate the problems into English for better understanding. 2015 ACM/ICPC Asia Regional Shenyang Online. 这个赛季的OpenCup...
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zimpha's blog | zimpha.github.io Reviews

https://zimpha.github.io

XVI Open Cup named after E.V. Pankratiev. Grand Prix of Japan. 这套题目的来源是Japan Alumni Group Summer Camp 2015 Day 4, 我的代码可能即将会出现在这个 链接. 这里是题解时间, 英文翻译请参考之前的某篇博客. 由于还在比赛, 题解会在比赛结束后若干个小时放出, 我的代码也会放在github上. English Translation for ONTAK 2015. English Translation for Potyczki Algorytmiczne 2015. Potyczki Algorytmiczne 2015 has just begun. As usual, the statements are only in Polish. So, I will translate the problems into English for better understanding. 2015 ACM/ICPC Asia Regional Shenyang Online. 这个赛季的OpenCup...

INTERNAL PAGES

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about | zimpha's blog

http://zimpha.github.io/about

主题 - NexT.Mist.

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KTU Programming Camp | zimpha's blog

http://zimpha.github.io/2015/09/15/ktu-programming-camp

挂在CF gym上的4套比赛, 最近闲着无聊做了一下, 题目都比较简单, 可以闲着的时候练练手. 稍微写了一些简要题解, 貌似官方也有题解, 可以到cf上找一下. KTU Programming Camp (Day 1). Problem A. Strong parentheses sequence. 给出一个强括号序列$A$(首尾分别是(和)的平衡括号序列). 然后对于所有$i 1 le j i lt i 2 le j 2$并且$A[i 1.j 1]$和$A[i 2.j 2]$都是强括号序列, 找到最短的包含他们的强括号序列, 输出这些序列的和. 数据规模: $2 le A le 100000$. 把一对匹配括号当做树上的节点, 于是可以根据序列$A$构造出一棵树. 于是只要统计每个节点对答案的贡献即可. Problem B. Retrospective Sequence. 数据规模: $1 le n le 20, 1 le m le 10 {18}$. Problem C. Power. 数据规模: $1 le n, m le 25$. 数据规模: $1 le n le 15$. 数据规模: $1 ...

3

XV Open Cup named after E.V. Pankratiev. Grand Prix of Central Europe (AMPPZ 2014) | zimpha's blog

http://zimpha.github.io/2015/09/15/xv-opencup-gp3

XV Open Cup named after E.V. Pankratiev. Grand Prix of Central Europe (AMPPZ 2014). 同样是去年final训练是做的, 题目来源是AMPPZ 2014, 是波兰那边进CERC的预选赛. 似乎有一定量的智商题, 需要找出结论. Problem A. The Lawyer. 给出$m$天中的$n$个任务的开始时间$a i$结束时间$b i$, 对于每一天, 找出两个不相交的任务. 数据规模: $2 le n le 500000, 1 le m le 20, 1 le a i lt b i le 80000000$. 对于每一天记录结束时间最早的和开始时间最晚的两个任务, check一下即可. 复杂度$O(n m)$. Problem B. Petrol. 给出一个$n$个点$m$条边的带权无向图, 然后有$s$个加油站. 给出$q$个询问, 每次给出起点$x i$, 终点$y i$, 以及油箱容量$b i$, 问能否从$x i$到$y i$. Problem C. The Prices. 数据规模: $1 le n le 50...

4

分类: jag | zimpha's blog

http://zimpha.github.io/categories/opencup/jag

XVI Open Cup named after E.V. Pankratiev. Grand Prix of Japan. 主题 - NexT.Mist.

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zimpha's blog

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World Finals 2002 - Honolulu. Problem A. Balloons in a Box. 将$n$个气球放到一个长方体盒子里面, 然后气球会一直膨胀, 直到碰到盒壁或者其他气球. 先要求你找到一个放气球的顺序, 使得最后最后气球占据的体积最大. 数据规模: $1 le n le 6$. 主题 - NexT.Mist.

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HDU 4582 – DFS spanning tree(贪心) | HardBird

http://www.hardbird.net/hdu-4582-dfs-spanning-tree(贪心)

HDU 4582 – DFS spanning tree 贪心. 大意 对一个无向图,给定一个dfs生成树,定义T-Simple Circle 有且只有一条边不在dfs树上的环。 Define ALL(a) a.begin(), a.end(). Define clr(a, x) memset(a, x, sizeof a). Define pb push back. HDU 5352 – MZL’s City 费用流. HDU 4123 – Bob’s Race 树的直径 RMQ. WP Cumulus Flash tag cloud by Roy Tanck.

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HDU 6371 – Hotaru’s problem(Manacher算法) | HardBird

http://www.hardbird.net/hdu-6371-hotarus-problem(manacher算法)

HDU 6371 – Hotaru’s problem Manacher算法. 扯淡 2015多校第七场的C. 虽然是非负整数序列,但明显是要上字符串算法的题,各种不情愿做啊…最后没办法了,大帅不在,我只能单开这题了,还好最后想出正解来了,虽然最后只写完没时间debug了,不过我还是成功在赛后10分钟AC了,我想静静,但我更想大帅……. Sbegin(); it- ) { int j=*it; if( j-i)/2 ans)break; if(Ma[i] 0 & (j-i)/2 ans) { ans=(j-i) 1; break; } } } printf("Case #%d: %d n", kase, ans*3); } return 0; }. Define pb push back. Case #%d: %d n". HDU 4767 – Bell 贝尔数 矩阵快速幂 中国剩余定理. SGU 185 – Two shortest 最短路 最大流. WP Cumulus Flash tag cloud by Roy Tanck.

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About me | HardBird

http://www.hardbird.net/about-me

WP Cumulus Flash tag cloud by Roy Tanck.

hardbird.net hardbird.net

HDU 4579 – Random Walk(高斯消元) | HardBird

http://www.hardbird.net/hdu-4579-random-walk(高斯消元)

HDU 4579 – Random Walk 高斯消元. 思路 典型的高斯消元求概率dp,x[i]表示走到n需要走多少次的期望,则x[i]=sigma{p[j]*x[j]} 1.然后列矩阵,消元就好。 Define clr(a, x) memset(a, x, sizeof a). HDU 4126 – Genghis Khan the Conqueror 生成树 树链剖分. HDU 4767 – Bell 贝尔数 矩阵快速幂 中国剩余定理. WP Cumulus Flash tag cloud by Roy Tanck.

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HDU 4126 – Genghis Khan the Conqueror(生成树+树链剖分) | HardBird

http://www.hardbird.net/hdu-4126-genghis-khan-the-conqueror(生成树树链剖分)

HDU 4126 – Genghis Khan the Conqueror 生成树 树链剖分. 大意 在一个稠密的无向连通图中,无重边,无自环,有Q次操作,每次改变一条边的权值 只增不减 ,要求求出改变后的图的最小生成树的权值,最终输出Q次最小生成树权值的平均值。 如果改变的是生成树上的边,情况就有两种了 该边不再作为生成树上的边,需要找到权值最小替换边 该边依旧在生成树上,此次生成树的权值就是原生成树权值 边的改变量。 网上大部分的题解都是用dp来维护的替换边权值,训练赛的时候并没有想到dp,只想到树剖了……也不是什么正解,也不再多解释了,就当是保存份代码了…. Son[u] & e.v! U) ans =cost; else ans =cost-wei[v] min(query(p[v], 1, pos, 1), w); } printf("%.4f n", ans/q); } return 0; }. Define clr(a, x) memset(a, x, sizeof a). Define ls (rt 1). Define rs (ls 1). Define lson l, mid, ls.

hardbird.net hardbird.net

HardBird | 别低头,王冠会掉。别流泪,坏人会笑。 | 第 22 页

http://www.hardbird.net/page/22

UVA 12083 – Guardian of Decency(二分图最大独立集). 题目链接 大意 一个老师要带一些学生出去玩,但带出去的任意两个学生至少[…]. UVA 11419 – SAM I AM(二分图最小点覆盖). Codeforces 514D – R2D2 and Droid Army(枚举 二分). 题目链接 大意 有n个目标站成一排,每个目标有m个属性,最多可以发动k[…]. HDU 2444 – The Accomodation of Students(二分图匹配). 题目链接 大意 n个人中,有m对相互认识的关系,问能否分成两组,同一组[…]. UVA 11478 – Halum(差分约束). UVA 11029 – Leading and Trailing. 题目链接 大意 求n k的前三位数和后三位数(输入保证答案存在)。 UVA 11865 – Stream My Contest(二分 最小树形图). UVA 10816 – Travel in Desert(二分 最短路). UVA 11183 – Teen Girl Squad(最小树形图).

hardbird.net hardbird.net

HDU 5029 Relief grain(树链剖分+线段树) | HardBird

http://www.hardbird.net/hdu-5029-relief-grain(树链剖分线段树)

HDU 5029 Relief grain 树链剖分 线段树. Query(1, 1e5, 1):0); } for(int i=1; i =n; i ) printf("%d n", ans[i]); } return 0; }. Pragma comment(linker, "/STACK:1024000000,1024000000"). Define ALL(a) a.begin(), a.end(). Define clr(a, x) memset(a, x, sizeof a). Define pb push back. Define mp make pair. Define ls (rt 1). Define rs (ls 1). Define lson l, mid, ls. Define rson mid 1, r, rs. HDU 5381 – The sum of gcd 莫队算法. HDU 5383 – Yu-Gi-Oh! WP Cumulus Flash tag cloud by Roy Tanck.

hardbird.net hardbird.net

HDU 5383 – Yu-Gi-Oh!(费用流 | KM最大权匹配) | HardBird

http://www.hardbird.net/hdu-5383-yu-gi-oh(费用流-km最大权匹配)

HDU 5383 – Yu-Gi-Oh! Qempty() { int u=q.front(); q.pop(); inq[u]=0; for(int i=head[u]; i; i=edge[i].nxt) { Edge& e=edge[i]; if(e.cap e.flow & d[e.v] d[u] e.cost) { d[e.v]=d[u] e.cost; p[e.v]=i; a[e.v]=min(a[u], e.cap-e.flow); if(! Inq[ev]) { q.push(e.v); inq[e.v]=1; } } } } if(d[t]= oo)return false; flow =a[t]; cost =a[t]*d[t]; int u=t; while(u! Define clr(a, x) memset(a, x, sizeof a). Tuner[i] & lev[i] lev[x]= l & atk[x] atk[i] a) { if(tuner[x]) g[x][i]=max(g[x][i], a-atk[x]-atk[i]); else g[i][x]=max(g[...

hardbird.net hardbird.net

HDU 5381 – The sum of gcd(莫队算法) | HardBird

http://www.hardbird.net/hdu-5381-the-sum-of-gcd(莫队算法)

HDU 5381 – The sum of gcd 莫队算法. Define ALL(a) a.begin(), a.end(). Define clr(a, x) memset(a, x, sizeof a). Define pb push back. Define mp make pair. SGU 185 – Two shortest 最短路 最大流. HDU 5029 Relief grain 树链剖分 线段树. WP Cumulus Flash tag cloud by Roy Tanck.

hardbird.net hardbird.net

HardBird | 别低头,王冠会掉。别流泪,坏人会笑。 | 第 2 页

http://www.hardbird.net/page/2

CodeForces 593D Happy Tree Party LCA 并查集. 题目链接 题意 一个含有n个[…]. CodeForces 592D Super M 树的直径. 题目链接 题意 一棵有n个点[…]. CodeForces 575B Bribes 树链剖分. 题目链接 题意 给一个n个点[…]. UESTC 1219 – Ba Gua Zhen CCPC-E. 题目链接 题意 给一个n个点[…]. ZOJ 3911 – Prime Query 线段树. 题目链接 题意 给一个非负整[…]. HDU 5406 – CRB and Apple 费用流. 题目链接 题意 一棵树上有n个苹果,每个苹[…]. HDU 5468 – Puzzled Elena 莫比乌斯反演. 题目链接 题意 一个以结点1[…]. WP Cumulus Flash tag cloud by Roy Tanck.

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XVI Open Cup named after E.V. Pankratiev. Grand Prix of Japan. 这套题目的来源是Japan Alumni Group Summer Camp 2015 Day 4, 我的代码可能即将会出现在这个 链接. 这里是题解时间, 英文翻译请参考之前的某篇博客. 由于还在比赛, 题解会在比赛结束后若干个小时放出, 我的代码也会放在github上. English Translation for ONTAK 2015. English Translation for Potyczki Algorytmiczne 2015. Potyczki Algorytmiczne 2015 has just begun. As usual, the statements are only in Polish. So, I will translate the problems into English for better understanding. 2015 ACM/ICPC Asia Regional Shenyang Online. 这个赛季的OpenCup...

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Zimbra Server 2 Go. บร การต ดต ง Zimbra. IP Blacklist Monitoring Service. Zimbra Open Source Off-Site Backup. Zimbra High Availability (Active/Standby). Zimbra Multi Site System. บร ษ ท ส นม นคง ประก นภ ย จำก ด (มหาชน) ใช Zimbra แทน MS Exchange 2010 ลดค าล ขส ทธ ซอฟต แวร. บร ษ ท เพาเวอร ไลน เอ นจ เน ยร ง จำก ด (มหาชน) เล อกใช Zimbra แทน MS Exchange 2007. บร ษ ท น ำตาลม ตรผล เล ง Zimbra ช วยลดค าใช จ ายล ขส ทธ จากเคยใช Exchange. บร ษ ท ไทยย เน ยนสก รน อต ต ดใจ Zimbra ขอ Upgrade เป น VPS ให พน กงานใช.