bimelab.blogspot.com
APPLICATIONS OF MATLAB ON ENGINEERING PROBLEMS: 12/31/2006 - 01/07/2007
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APPLICATIONS OF MATLAB ON ENGINEERING PROBLEMS. 於 1/04/2007 12:08:00 上午. 訂閱: 文章 (Atom). 為維持本課程進度,只好增加每章作業題。"每章作業題"均有限時,繳交期限為當天午夜前,逾時關閉回應功能,不再計分。請按連結"每週習題請按此==>"之按鈕作答,或直接進入 http:/ exam4matlab.blogspot.com/. 12288; 以前所提供之作業繳交方式仍然有效,將繼續計分直到期末。由於沒有期末考,故一切作業均在明年一月十二日午夜到期,逾期不收件,請同學注意。 每週習題請按此==>. Blogger, Nature lover, Like to swim, travel and photograph. Host of the blog Hut for Life, Work and Pleasure ( http:/ hut4u.blogspot.com/. 部落客, 愛好自然、游泳, 旅遊及攝影,草堂雜記老人。 .
diowking.blogspot.com
胖威的懶窩: 家庭煮夫奧利佛 新鮮草莓
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Wednesday, May 21, 2008. Subscribe to: Post Comments (Atom). View my complete profile.
diowking.blogspot.com
胖威的懶窩: May 2008
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Wednesday, May 21, 2008. 害我好想去咕狗工作唷 不出百步 必有食物! Subscribe to: Posts (Atom). View my complete profile.
diowking.blogspot.com
胖威的懶窩: November 2006
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Thursday, November 30, 2006. 熱傳模組的建立(續) 穩態邊界所有情形. Disp('Now we will divide the 2-D plane for FDE'). Too choose the divide element by setting the side. R=input('Please input m row of the matrix you want = ');. C=input('Please input n column of the matrix you want = ');. V=reshape(v,r,c);. Set up a matrix to number every element of the matrix. After observing the FDE matrix, derive down rule code. H=input('The convection coeffcient is '). K=input('The conduction coeffcient is '). B( j-1)*r 1,1)=-Tu;. B(r*h...
diowking.blogspot.com
胖威的懶窩: 換顆腦袋救通膨?
http://diowking.blogspot.com/2008/05/blog-post_21.html
Wednesday, May 21, 2008. Subscribe to: Post Comments (Atom). View my complete profile.
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胖威的懶窩: June 2006
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Tuesday, June 06, 2006. 唉 被老師抓到在後面調皮.orz 阿怎都沒人來XD. 推薦一下韓劇 春天華爾滋 音樂風景都很美 劇中也有人用德文說話 應該八@@? 在奧地利取景 好美 老師 帶張風景明信片來嚐嚐如何. Subscribe to: Posts (Atom). View my complete profile.
diowking.blogspot.com
胖威的懶窩: 綠金產業新思維:從搖籃到搖籃
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Wednesday, May 21, 2008. Subscribe to: Post Comments (Atom). View my complete profile.
diowking.blogspot.com
胖威的懶窩: December 2006
http://diowking.blogspot.com/2006_12_01_archive.html
Thursday, December 14, 2006. 所以由此可以建立下列平衡式:k{[t(i-1) t(i)]/2 }{0.5*[R(i-1) R(i)]}*(2π)}[T(i-1)–T(i)] / Δr+k{[t(I 1) t(i)]/2 }{0.5*[R(i 1) R(i)}*(2π)}[T(i 1)–T(i)] / Δr+2h(i)*2πr(i)Δr[Ta-T(i)] = 0. Ka=k*{[t(i-1) t(i)]/2 };Kb=k*{[t(i 1) t(i)]/2 }. Ka[R(i-1) R(i)]/Δr*[T(i-1)–T(i)] Kb[R(i 1) R(i)]/Δr*[T(i 1)–T(i)] 4h(i)r(i)Δr[Ta-T(i)]=0. 再設 p(i)=Ka*[R(i-1) R(i)]/Δr;. Q(i)=Kb*[R(i 1) R(i)]/Δr; s(i)=4*h(i)*R(i)*Δr. VpT(i-1)-(p q s)T(i) qT(i 1)=-sTa i=2,3,…M-1. R=Ri(最內圈)時,Qfin= - k(1) t(1)(2πR(1)[dT/dr]. While ...