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nameless | pgf2.blogspot.com Reviews
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暇つぶし
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1 nameless
2 暇つぶし
3 セル・オートマトンと戯れたい
4 ドゥッチ数列 wikipedia
5 n 組の整数の元からなる数列
6 有限回の再帰で元が必ずすべて 0 になる
7 有限回の再帰で元がすべて 0 になる
8 有限回の再帰の中で元がすべて 0 になることはない
9 無限回の再帰の中で元がすべて 0 に収束する
10 元は整数のみ前提
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nameless,暇つぶし,セル・オートマトンと戯れたい,ドゥッチ数列 wikipedia,n 組の整数の元からなる数列,有限回の再帰で元が必ずすべて 0 になる,有限回の再帰で元がすべて 0 になる,有限回の再帰の中で元がすべて 0 になることはない,無限回の再帰の中で元がすべて 0 に収束する,元は整数のみ前提,コードも、もうちょっとどうにかしたい,けど一旦保存,投稿者 pgf2,0 件のコメント,メールで送信,blogthis,twitter で共有する,facebook で共有する,前の投稿
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nameless | pgf2.blogspot.com Reviews

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1

nameless: 2011-08

http://pgf2.blogspot.com/2011_08_01_archive.html

65339;数] ゴロムの自己記述数列. Golomb sequence - Wikipedia, the free encyclopedia. 9670; n = 50 までの数列. F(1) = 1 f(n 1) = 1 f(n 1 f(f(n) ) (n = 0). 9670; n 番目の数を求める(再帰) (xyzzy-lisp). 8251; 未完成。 9670; n 番目の数を求める(ループ) (xyzzy-lisp). 9632; そのいち(失敗). 8251; n = 131 でずれはじめる. F(130) = 24 f(131) = 25 → 24 が正解 f(132) = 25. 9632; そのに(失敗) . 追記)2011-09-02. Defun f(n) (cond ( = n 1) 1) (t (let ( x 2) (count 1) (a 0) (b 0) (c 0) (s 1) (sa 2) (loop (if (not (. どこでずれ始めたか調べるのがめんどくさ .(げふん。 9670; Problem 127 - Project Euler. 0) { mult...

2

nameless: 2011-07

http://pgf2.blogspot.com/2011_07_01_archive.html

65339;数] 階乗. 自然数 n の階乗(かいじょう、英語: factorial)n! とは、1 から n までの自然数の総乗. N * (n - 1) * . * 3 * 2 * 1 = Pi {k=1} {n} k. のことを言う。 例えば、6! 65309;6・5・4・3・2・1=720 である。階乗数は n が大きくなるにつれて驚くほど大きな数になるので記号として「! 65309;1 と約束する。これは、(n-1)! 1 = 1 と考えられるため、あるいは、n! が異なる n 個のものを並べる順列の総数 nPn に一致し、0 個のものを並べる順列は「何も並べない」という一通りがあると考えられるため、などと解釈できる。 順列では、互いに異なる n 個のものから n 個全部または n-1 個を選んで線状に並べる方法はn! 通りあり、互いに異なる n 個のものから n 個全部を選んで円環状に並べる方法は (n-1)! Defun factorial(n) (if (. 65339;数] パンデジタル数. 9670; パンデジタル数(0-9 10桁)であるか判断する. Defun is-pandig...

3

nameless: 2012-09

http://pgf2.blogspot.com/2012_09_01_archive.html

Anarchy golf - Fibonacci Numbers with CommonLisp (clisp). 次は Fibonacci Numbers で。 Anarchy golf - Fibonacci Numbers. 9670; Fibonacci Numbers. F(1)=1, f(2)=1, f(n)=f(n-1) f(n-2). F(1) から f(46) まで出力する. Do ( a 1)(b 1)(c 0)(x 0 (1 x) ) ( = x 46) (format t " A %" a) (setq c a) (setq a b) (setq b ( c b) ). Do* ( a 0 (- b a) (b 1 ( a b) ) ( a 1836311903) (format t" [ :; A % ]"a a). 12288;  ↓. Do*( a 0(- b a) (b 1( a b) )( a 1836311903) (format t" [ :; A % ]"a a). 12288;  ↓. 12288;  ↓. 紆余曲折を経てやっと 66 文字。 Class tes...

4

nameless: 2011-06

http://pgf2.blogspot.com/2011_06_01_archive.html

65339;Project Euler] Problem 80. かいへいほうは、ほぼこぴぺ( http:/ www.shido.info/gb/guestbook.php? Id=1799 )。 Defun extraction(n len) (let ( ls '() ) (do ( x n) (i 0) (s 1) (. I qty) retval) (if (/= n (/ (expt (numerator (rational (sqrt n) ) 2) (expt (denominator (rational (sqrt n) ) 2) ) (setq retval ( retval (sum-100-digit n) ) ) ) (problem80 100) 40886. 65339;数] 平方根. 平方根の最上位から 100 桁欲しい。 無理。精度的に。最上位 15 桁くらいが限界。 65288;時間切れ。続く). 65339;Project Euler] Problem 79. 65339;Project Euler] Problem 69. N 1) (setq phi (- phi...

5

nameless: 2012-03

http://pgf2.blogspot.com/2012_03_01_archive.html

一応、再帰、だと信じている。 F(0) = 0 f(1) = 1 f(n) = f(n-1) f(n-2) ( n = 2 ). 9671; プログラム (ver バッチファイル). Echo off CALL :FIBONACCI %1 ECHO %ERRORLEVEL% EXIT /b 0 :FIBONACCI SETLOCAL SET /A f = 0 IF %1 LEQ 0 ( EXIT /b 0 ) IF %1 EQU 1 ( EXIT /b 1 ) SET /A n1 = %1 -1 CALL :FIBONACCI %n1% SET /A f = %ERRORLEVEL% SET /A n2 = %1 - 2 CALL :FIBONACCI %n2% SET /A f = %f% %ERRORLEVEL% EXIT /B %f% ENDLOCAL. Picture Window テンプレート. Powered by Blogger.

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Last-modified: 2011-11-30 (水) 23:07:30 (1729d). Blog: http:/ pgf2.blogspot.com/. SPOJ Problem Set (classical). SPOJ Problem Set (challenge). SPOJ Problem Set (partial). SPOJ Problem Set (tutorial). SPOJ Problem Set (partial). SPOJ Problem Set (classical). SPOJ Problem Set (tutorial). SPOJ Problem Set (challenge). Site admin: a.terada. PukiWiki 1.4.7. Based on "PukiWiki" 1.3 by yu-ji. Designed by 180.style. Powered by PHP . HTML convert time: 0.017 sec.

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nameless

Ducci Sequence (途中). 人にはそうしたいときだってあると思うんだ . 。 9670; Ducci Sequence. 9632; n が 2 のべき乗の場合. 9632; n が 2 のべき乗以外の場合. 有限回の再帰の中で周期性を持つようになる(元がすべて 0 になることはない). 9671; プログラム (Common Lisp系). N は 1 を除く 2 のべき乗のみ処理する. いろいろ端折ってる . 気がする. 実行 (ducci-seq (make-array 4 :initial-contents '(8 11 2 7) ) #(8 11 2 7) #(3 9 5 1) #(6 4 4 2) #(2 0 2 4) #(2 2 2 2) #(0 0 0 0). 実行 (ducci-seq (make-array 4 :initial-contents '(1 1 0 1) ) #(1 1 0 1) #(0 1 1 0) #(1 0 1 0) #(1 1 1 1) #(0 0 0 0) nil. N が 2 のべき乗以外も実装したい。

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