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Solutions Looking For Problems

Solutions Looking For Problems. Coding for the love of it. Calculate π by throwing darts. We can approximate pi using nothing more than random numbers and some simple geometry: in essence, we randomly throw darts at a square board of side r; within the square we inscribe a quadrant of a circle of radius r with its centre at (0, 0). We count all of the 'throws'; if a dart lands within the quadrant, we also count a 'hit'. For a large number of throws, we see that:. Hits area of quadrant. Def is a hit(self):.

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Solutions Looking For Problems | randombitsofcode.blogspot.com Reviews
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Solutions Looking For Problems. Coding for the love of it. Calculate π by throwing darts. We can approximate pi using nothing more than random numbers and some simple geometry: in essence, we randomly throw darts at a square board of side r; within the square we inscribe a quadrant of a circle of radius r with its centre at (0, 0). We count all of the 'throws'; if a dart lands within the quadrant, we also count a 'hit'. For a large number of throws, we see that:. Hits area of quadrant. Def is a hit(self):.
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1 skip to main
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3 usr/bin/env python
4 import random
5 import math
6 class throw
7 def init self
8 the origin
9 def distance self
10 return self distance
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skip to main,skip to sidebar,usr/bin/env python,import random,import math,class throw,def init self,the origin,def distance self,return self distance,main class,class montecarlo,initialise everything,selfhits = 0,selfthrows = 0,selfpi = 0,selfthrows = 1
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Solutions Looking For Problems | randombitsofcode.blogspot.com Reviews

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Solutions Looking For Problems. Coding for the love of it. Calculate π by throwing darts. We can approximate pi using nothing more than random numbers and some simple geometry: in essence, we randomly throw darts at a square board of side r; within the square we inscribe a quadrant of a circle of radius r with its centre at (0, 0). We count all of the 'throws'; if a dart lands within the quadrant, we also count a 'hit'. For a large number of throws, we see that:. Hits area of quadrant. Def is a hit(self):.

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Solutions Looking For Problems: Evolve some text

http://randombitsofcode.blogspot.com/2009/02/evolve-some-text.html

Solutions Looking For Problems. Coding for the love of it. Happy Birthday Darwin. And Python rocks. The string we will work towards. Target = sys.argv[1]. Target = "from so simple a beginning endless forms most beautiful and most wonderful have been, and are being, evolved.". Get ascii character set. For i in range(32, 127):. How many candidates will we spawn in each generation. A list to hold our candidates. Class representing a character in our candidate. Def init (self, char = " ):. Create a new list.

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Solutions Looking For Problems: Calculate π by throwing darts

http://randombitsofcode.blogspot.com/2009/03/calculate-by-throwing-darts.html

Solutions Looking For Problems. Coding for the love of it. Calculate π by throwing darts. We can approximate pi using nothing more than random numbers and some simple geometry: in essence, we randomly throw darts at a square board of side r; within the square we inscribe a quadrant of a circle of radius r with its centre at (0, 0). We count all of the 'throws'; if a dart lands within the quadrant, we also count a 'hit'. For a large number of throws, we see that:. Hits area of quadrant. Def is a hit(self):.

3

Solutions Looking For Problems: Permutations

http://randombitsofcode.blogspot.com/2009/02/permutations.html

Solutions Looking For Problems. Coding for the love of it. We want to work out all the possible arrangements of a list of. We don't know. But we do know how to do it: seed with a list containing a single list containing a single item:. Then step through each of the lists in our list, and make copies, inserting the next item ( 'b'. At each index, so we get. A'], ['a', '. Then we take this list as our seed and go round again, inserting the next item ( 'c'. B', 'a'], ['b', '. A'], ['b', 'a', '. When we're d...

4

Solutions Looking For Problems: 2009-02

http://randombitsofcode.blogspot.com/2009_02_01_archive.html

Solutions Looking For Problems. Coding for the love of it. We want to work out all the possible arrangements of a list of. We don't know. But we do know how to do it: seed with a list containing a single list containing a single item:. Then step through each of the lists in our list, and make copies, inserting the next item ( 'b'. At each index, so we get. A'], ['a', '. Then we take this list as our seed and go round again, inserting the next item ( 'c'. B', 'a'], ['b', '. A'], ['b', 'a', '. When we're d...

5

Solutions Looking For Problems: 2009-03

http://randombitsofcode.blogspot.com/2009_03_01_archive.html

Solutions Looking For Problems. Coding for the love of it. Calculate π by throwing darts. We can approximate pi using nothing more than random numbers and some simple geometry: in essence, we randomly throw darts at a square board of side r; within the square we inscribe a quadrant of a circle of radius r with its centre at (0, 0). We count all of the 'throws'; if a dart lands within the quadrant, we also count a 'hit'. For a large number of throws, we see that:. Hits area of quadrant. Def is a hit(self):.

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Solutions Looking For Problems

Solutions Looking For Problems. Coding for the love of it. Calculate π by throwing darts. We can approximate pi using nothing more than random numbers and some simple geometry: in essence, we randomly throw darts at a square board of side r; within the square we inscribe a quadrant of a circle of radius r with its centre at (0, 0). We count all of the 'throws'; if a dart lands within the quadrant, we also count a 'hit'. For a large number of throws, we see that:. Hits area of quadrant. Def is a hit(self):.

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