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dgoldblatt.com

David Goldblatt's website

A threading riddle - Solution. Published: Tue 30 June 2015. Updated: Tue 30 June 2015. In the last post. We looked at a threading problem that requires a some trickiness to solve. In this post, we'll reveal the tricks that we need. As a recap, we had two functions we set out to implement, that operate on an array of size. Void modify(size t index, int value);. This changes the element at position. Void wait until equal(size t index1, size t index2);. This blocks until the elements at positions. Then the ...

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A threading riddle - Solution. Published: Tue 30 June 2015. Updated: Tue 30 June 2015. In the last post. We looked at a threading problem that requires a some trickiness to solve. In this post, we'll reveal the tricks that we need. As a recap, we had two functions we set out to implement, that operate on an array of size. Void modify(size t index, int value);. This changes the element at position. Void wait until equal(size t index1, size t index2);. This blocks until the elements at positions. Then the ...
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David Goldblatt's website | dgoldblatt.com Reviews

https://dgoldblatt.com

A threading riddle - Solution. Published: Tue 30 June 2015. Updated: Tue 30 June 2015. In the last post. We looked at a threading problem that requires a some trickiness to solve. In this post, we'll reveal the tricks that we need. As a recap, we had two functions we set out to implement, that operate on an array of size. Void modify(size t index, int value);. This changes the element at position. Void wait until equal(size t index1, size t index2);. This blocks until the elements at positions. Then the ...

INTERNAL PAGES

dgoldblatt.com dgoldblatt.com
1

Lock-free reads through data replication

http://www.dgoldblatt.com/lock-free-reads-through-data-replication.html

Lock-free reads through data replication. Published: Wed 29 April 2015. Updated: Wed 29 April 2015. To accomplish this, we'll keep two copies of our data structure. The writer needs to update both copies of the data, one after the other, in order to logically complete a write. If the writer blocks, it will be blocked inside an update to only one of the copies. The readers can then proceed by reading from the other copy, giving us the lock-freedom property we sought. Reader-writer locks provide safe acces...

2

David Goldblatt's website - programming

http://www.dgoldblatt.com/tag/programming.html

A threading riddle - Solution. Published: Tue 30 June 2015. Updated: Tue 30 June 2015. In the last post. We looked at a threading problem that requires a some trickiness to solve. In this post, we'll reveal the tricks that we need. As a recap, we had two functions we set out to implement, that operate on an array of size. Void modify(size t index, int value);. This changes the element at position. Void wait until equal(size t index1, size t index2);. This blocks until the elements at positions. Then the ...

3

A threading riddle

http://www.dgoldblatt.com/a-threading-riddle.html

Published: Wed 24 June 2015. Updated: Wed 24 June 2015. The two key primitives used as building blocks for (blocking) concurrent algorithms are mutexes and condition variables, showing up in C as. In this post, I'll describe a pair of functions that can be simply described, but whose implementation requires a tricky use of these primitives. Suppose we have an array of. S There are two functions we want to implement:. Void modify(size t index, int value);. This changes the element at position. If a call to.

4

About

http://www.dgoldblatt.com/pages/about.html

Hi, I'm David Goldblatt; you've discovered my blog. Hopefully you found it interesting. In my non-internet life I'm a software engineer at Google, where I work on performance teams in the frontend server of the search stack. You can email me at davidtgoldblatt@gmail.com. Proudly powered by Pelican. Which takes great advantage of Python. The theme is by Smashing Magazine.

5

David Goldblatt's website - Blog

http://www.dgoldblatt.com/category/blog.html

A threading riddle - Solution. Published: Tue 30 June 2015. Updated: Tue 30 June 2015. In the last post. We looked at a threading problem that requires a some trickiness to solve. In this post, we'll reveal the tricks that we need. As a recap, we had two functions we set out to implement, that operate on an array of size. Void modify(size t index, int value);. This changes the element at position. Void wait until equal(size t index1, size t index2);. This blocks until the elements at positions. Then the ...

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David Goldblatt's website

A threading riddle - Solution. Published: Tue 30 June 2015. Updated: Tue 30 June 2015. In the last post. We looked at a threading problem that requires a some trickiness to solve. In this post, we'll reveal the tricks that we need. As a recap, we had two functions we set out to implement, that operate on an array of size. Void modify(size t index, int value);. This changes the element at position. Void wait until equal(size t index1, size t index2);. This blocks until the elements at positions. Then the ...

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